4x^2+88x-480=0

Solution for 4x^2+88x-480=0 equation:

4x^2+88x-480=0

a = 4; b = 88; c = -480;
Δ = b2-4ac
Δ = 882-4·4·(-480)
Δ = 15424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15424}=\sqrt{64*241}=\sqrt{64}*\sqrt{241}=8\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-8\sqrt{241}}{2*4}=\frac{-88-8\sqrt{241}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+8\sqrt{241}}{2*4}=\frac{-88+8\sqrt{241}}{8}
$